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Originally Posted by zlatanov
well, what mrki said only we'll need 3 such balls with 2 teams in each, assuming that Sevilla would go to pot 2 and AEK pot 4, something that will be known for sure once all the other games are played, the winners are known, and then we can compare their coefficients with those of Sevilla and AEK.
Let's say Sevilla's coeff. is high enough for pot 2, which it is, and AEK's - for pot 4.
Now let's assume - just an example - that the team with highest coeff in pot 3 is Benfica. This means that Benfica would move to pot 2 if Sevilla goes out, with AEK joining pot 4.
At the same time, let's assume - again just an example - that Stuttgart is the team with the highest coeff in pot 4 i.e. they would move to pot 3 if Sevilla goes out and AEK moves to pot 4.
Then all we need to do is have 1 ball in pot 2 like this - Sevilla/Benfica, 1 ball in pot 3 - Benfica/Stuttgart, and one ball in pot 4 - Stuttgart/AEK
Capito? 
P.S. If AEK's coeff is high enough for pot 3, then we'd need 2 balls, and not 3, with 2 teams in each one. |
Perfect, thanx
Although we have another problem here.
In groups A-D we can have only 2 Spanish teams while the other 2 will have to be in groups E-H.
Also one of AEK/Olympiacos will have to be in groups A-D while the other in groups E-H
Now we can have a situation when (if the ball says Sevilla/Ajax) Sevilla can not play in groups A-D while Ajax can not play in groups E-H and it will be impossible to make that draw.
I don't know if you follow me, but this is a big possibility and because of this the draw (which is usually 30%-50% orchestred) may easily be 99% orchestred.
They'll find a way, i'm sure. But it will be really confusing for those who aren't absolutely familiar with how these things go
